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AgsXMPP Http Proxy
danielgielow 2011-04-20, 16:34 #1
Member since Apr 2011 · 4 posts
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Subject: AgsXMPP Http Proxy
Hi,

I needed configure a proxy in my agsxmpp conection. I looked a lot, but don't found a simple example where i could tell host, port, username and password.

My current connection it is:

  1. static void Main(string[] args)
  2.         {
  3.             XmppClientConnection xmpp = new XmppClientConnection();
  4.             xmpp.Server = "domain";
  5.             xmpp.ConnectServer = "xxx.xx.xxx.xxx";
  6.             xmpp.Username = "user";
  7.             xmpp.Password = "password";
  8.             xmpp.AutoResolveConnectServer = false;
  9.             xmpp.OnLogin += xmpp_OnLogin;
  10.             xmpp.OnError += xmpp_OnError;
  11.             xmpp.OnAuthError += xmpp_OnAuthError;
  12.             xmpp.Open();
  13.  
  14.             lock (xmpp)
  15.             {
  16.                 if (Monitor.Wait(xmpp, 400000))
  17.                 {
  18.                     Console.WriteLine("Connected. Authenticated: " + xmpp.Authenticated);
  19.                 }
  20.  
  21.             }
  22. }
  23.  
  24. static void xmpp_OnLogin(object sender)
  25.         {
  26.             lock (sender)
  27.             {
  28.                 Monitor.Pulse(sender);
  29.             }
  30.         }

Congratulations
Daniel Gielow Junior
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Alex 2011-04-20, 18:54 #2
Member since Feb 2003 · 2700 posts · Location: Germany
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XMPP is using persistent TCP/IP sockets by default. You can't proxy TCP sockets with the most proxy servers.
HTTP Proxy makes only sense when you use BOSH as transport layer for your connection. Then you can cast the xmppConection.ClientSocket propery to BoshClientSocket and set the Proxy.

Alex
Alexander Gnauck
AG-Software
danielgielow 2011-04-20, 19:20 #3
Member since Apr 2011 · 4 posts
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Hi,

How can i use BOSH as transport?
You have an example or link for me to see?

I'm starting with a little time XMPP.

Thanks for the help.
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Alex 2011-04-20, 19:53 #4
Member since Feb 2003 · 2700 posts · Location: Germany
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  1. _connection.SocketConnectionType    = agsXMPP.net.SocketConnectionType.Bosh;
  2. _connection.ConnectServer = "http://yourserver.com:5280/http-bind/";

and of course you need a server which supports BOSH.

Alex
Alexander Gnauck
AG-Software
danielgielow 2011-04-20, 21:07 #5
Member since Apr 2011 · 4 posts
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Good afternoon Alex,

It's hard to me because i am a beginner.
I try it with a on-line proxy:

            XmppClientConnection xmpp = new XmppClientConnection();
            xmpp.Server = "domain";
            xmpp.ConnectServer = "187.85.160.242";
            xmpp.Username = "user";
            xmpp.Password = "password";
            xmpp.AutoResolveConnectServer = false;
            xmpp.OnLogin += xmpp_OnLogin;
            xmpp.OnError += xmpp_OnError;
            xmpp.OnAuthError += xmpp_OnAuthError;

            xmpp.SocketConnectionType = SocketConnectionType.Bosh;
            var bosh = (BoshClientSocket)xmpp.ClientSocket;
            bosh.Address = "173.201.191.190";
            bosh.Port = 80;

            xmpp.Open();

And i get this error:

Invalid URI: The format of the URI could not be determined.


Daniel
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Alex 2011-04-21, 21:02 #6
Member since Feb 2003 · 2700 posts · Location: Germany
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your code is wrong, and you have no URL, only an IP.

  1. XmppClientConnection xmpp = new XmppClientConnection();
  2. xmpp.Server = "domain";
  3. xmpp.ConnectServer = "http://server.com:5280/http-bind/"; // your BOSH Url here only
  4. xmpp.Username = "user";
  5. xmpp.Password = "password";
  6. xmpp.AutoResolveConnectServer = false;
  7. xmpp.OnLogin += xmpp_OnLogin;
  8. xmpp.OnError += xmpp_OnError;
  9. xmpp.OnAuthError += xmpp_OnAuthError;
  10. xmpp.SocketConnectionType = SocketConnectionType.Bosh;
  11.  
  12. xmpp.Open();
Alexander Gnauck
AG-Software
danielgielow 2011-04-29, 01:11 #7
Member since Apr 2011 · 4 posts
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Alex,

This is not my case because I have a url.

Thanks for the help.
maincoon 2011-07-01, 16:25 #8
Member since May 2011 · 13 posts
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In reply to post #6
Is there a way to specify login and password for HTTP proxyes? Is URL scheme supports user:password@host/uri format?
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Alex 2011-07-01, 18:50 #9
Member since Feb 2003 · 2700 posts · Location: Germany
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The Proxy property of BoshClientSocket is what you are looking for.

Alex
Alexander Gnauck
AG-Software
maincoon 2011-07-02, 13:23 #10
Member since May 2011 · 13 posts
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OK, hope this should work:

                    case agsXMPP.net.SocketConnectionType.Bosh:
                        // setup connect url
                        connectUrl = "http://" + profile.proxyHost + ":" + profile.proxyPort;
                        // setup credentials for proxy
                        if ( profile.useProxyAuth == true ) {
                            BoshClientSocket sock = xmpp.ClientSocket as BoshClientSocket;
                            sock.Proxy.Credentials = new NetworkCredential(profile.proxyUser, profile.proxyPass);
                        }
                        xmpp.ConnectServer = connectUrl;

How about HttpPolling?
maincoon 2011-07-02, 16:55 #11
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In reply to post #9
Sorry, I've found PollClientSocket also. It's all clear now. Thanks!
maincoon 2011-07-05, 11:21 #12
Member since May 2011 · 13 posts
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Yep, wrong thread..
This post was edited on 2011-07-05, 11:22 by maincoon.
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